25c^2-20c+4=

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Solution for 25c^2-20c+4= equation:


Simplifying
25c2 + -20c + 4 = 0

Reorder the terms:
4 + -20c + 25c2 = 0

Solving
4 + -20c + 25c2 = 0

Solving for variable 'c'.

Factor a trinomial.
(2 + -5c)(2 + -5c) = 0

Subproblem 1

Set the factor '(2 + -5c)' equal to zero and attempt to solve: Simplifying 2 + -5c = 0 Solving 2 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -5c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -5c = 0 + -2 -5c = 0 + -2 Combine like terms: 0 + -2 = -2 -5c = -2 Divide each side by '-5'. c = 0.4 Simplifying c = 0.4

Subproblem 2

Set the factor '(2 + -5c)' equal to zero and attempt to solve: Simplifying 2 + -5c = 0 Solving 2 + -5c = 0 Move all terms containing c to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -5c = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -5c = 0 + -2 -5c = 0 + -2 Combine like terms: 0 + -2 = -2 -5c = -2 Divide each side by '-5'. c = 0.4 Simplifying c = 0.4

Solution

c = {0.4, 0.4}

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